c - 如何成功打印52张牌和5张非重复牌?

c - 如何成功打印52张牌和5张非重复牌?,第1张

我想填写并打印出52张卡片,然后成功打印5手5张非重复卡片,但之后它无法正常工作。我怎么能解决这个问题?

代码:

 #include <stdio.h>
 #include <stdlib.h>
 #include <time.h>

 /* handy typedefs */
 typedef unsigned char card;
 typedef unsigned char pairs;

 /* arrays for the names of things */
 static char *suits[4] = {"Hearts","Diamonds","Clubs","Spades"};
 static char *values[13]= {"Ace","Two","Three","Four","Five","Six",/
                        "Seven","Eight","Nine","Ten","Jack","Queen","King"};
 static char *colour[]= {"Black","Red"};

int main()
{
  card deck[52][24],*deckp;
  int s, c, a;

  for (s = 0; s < 4; s  )
  {
    for(c = 0; c < 13; c  )
    {
       sprintf(deck[(s * c)   c], "%s of %s", values[c], suits[s]);
    }
  }

  for(a = 0; a < 52; a  )
  {
    printf("%s\n", deck[a]);
  }

  int hand,cd,winner;

  int iRand;
  int i;
  int irand;

  srand(time(NULL));       /* seed the random number generator */

  for(cd=0;cd<5;cd  )
  {

    for(hand=0;hand<5;hand  )
    {
      /* deal the hands here */

    }
  }

  for (hand=0;hand<5;hand  )
  {
    printf("Hand %i:\n",hand 1 );
    for ( i = 0; i < 5; i  ) {
      irand = (rand() % 52);
      printf(" %s \n ", deck[irand]);
    }
  }
  /* determine the winner and print it */
  return 0;
}

void filldeck(card deck[52])
{
  return;
}

void shuffle(card deck[52])
{
  int i,rnd;
  card c;

  for(i=0;i<52;i  )
  {
    /* generate a random number between 0 & 51 */
    rnd=rand() * 52.0 / RAND_MAX;
    c = deck[i];
    deck[i] = deck[rnd];
    deck[rnd] = c;
  }
}

最佳答案:

1 个答案:

答案 0 :(得分:0)

deck[(s * c) c]替换为deck[s * 13 c]

本文经用户投稿或网站收集转载,如有侵权请联系本站。

发表评论

0条回复